1998 Gold Flake Open – Doubles

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Doubles
1998 Gold Flake Open
Final
ChampionsIndia Mahesh Bhupathi
India Leander Paes
Runners-upFrance Olivier Delaître
Belarus Max Mirnyi
Score6–7, 6–3, 6–2
Events
Singles Doubles
← 1997 · Gold Flake Open · 1999 →

Mahesh Bhupathi and Leander Paes were the defending champions. They successfully defended their title, defeating Olivier Delaître and Max Mirnyi in the final 6–7, 6–3, 6–2.

Seeds[edit]

Draw[edit]

Key[edit]

Draw[edit]

First round Quarterfinals Semifinals Final
1 Australia T Woodbridge
Australia M Woodforde
6 6  
  United States D DiLucia
Australia P Tramacchi
2 2   1 Australia T Woodbridge
Australia M Woodforde
6 1  
WC Germany L Burgsmüller
Germany R Schüttler
6 1 1   France A Clément
France J Golmard
7 6  
  France A Clément
France J Golmard
4 6 6   France A Clément
France J Golmard
3 2  
4 France O Delaître
Belarus M Mirnyi
6 6   4 France O Delaître
Belarus M Mirnyi
6 6  
WC India H Mankad
India G Natekar
1 2   4 France O Delaître
Belarus M Mirnyi
6 3 6
  Italy M Ardinghi
Italy V Santopadre
6 6     Italy M Ardinghi
Italy V Santopadre
3 6 2
  United Kingdom A Richardson
South Africa M Wakefield
2 1   4 France O Delaître
Belarus M Mirnyi
7 3 2
WC India S Kirtane
India V Uppal
2 4   2 India M Bhupathi
India L Paes
6 6 6
  United Kingdom B Cowan
Switzerland F Veglio
6 6     United Kingdom B Cowan
Switzerland F Veglio
2 6 7
Q South Africa D Nainkin
South Africa W Whitehouse
7 6   Q South Africa D Nainkin
South Africa W Whitehouse
6 4 6
3 United States J Salzenstein
United States J Stark
6 4     United Kingdom B Cowan
Switzerland F Veglio
6 1 6
  Czech Republic P Luxa
Israel E Ran
6 6   2 India M Bhupathi
India L Paes
2 6 7
  Germany M Hilpert
United States J Thomas
0 2     Czech Republic P Luxa
Israel E Ran
6 2 3
  Netherlands S Groen
Romania A Pavel
3 6 5 2 India M Bhupathi
India L Paes
3 6 6
2 India M Bhupathi
India L Paes
6 3 7

External links[edit]