1998 Chevrolet Cup – Doubles

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Doubles
1998 Chevrolet Cup
Final
ChampionsArgentina Mariano Hood
Argentina Sebastián Prieto
Runners-upItaly Massimo Bertolini
United States Devin Bowen
Score7–6, 6–7, 7–6
Events
Singles Doubles
← 1997 · Chile Open · 2000 →

Hendrik Jan Davids and Andrew Kratzmann were the defending champions, but did not participate this year.

Mariano Hood and Sebastián Prieto won the title, defeating Massimo Bertolini and Devin Bowen 7–6, 6–7, 7–6 in the final.

Seeds[edit]

Draw[edit]

Key[edit]

Draw[edit]

First round Quarterfinals Semifinals Final
1 Argentina D Orsanic
Mexico D Roditi
6 7  
  Brazil M Carlsson
Brazil F Meligeni
1 5   1 Argentina D Orsanic
Mexico D Roditi
4 4  
  Argentina P Albano
Spain J Balcells
6 6 3   South Africa L Bale
United Kingdom D Sapsford
6 6  
  South Africa L Bale
United Kingdom D Sapsford
7 4 6   South Africa L Bale
United Kingdom D Sapsford
6 6 4
3 Argentina M Hood
Argentina S Prieto
6 6   3 Argentina M Hood
Argentina S Prieto
4 7 6
  Spain A Berasategui
Spain J Burillo
3 2   3 Argentina M Hood
Argentina S Prieto
3 6 6
  Brazil G Kuerten
Brazil R Schlachter
3 6 2   Argentina L Arnold
Argentina M Puerta
6 0 3
  Argentina L Arnold
Argentina M Puerta
6 4 6 3 Argentina M Hood
Argentina S Prieto
7 6 7
  Italy M Bertolin
United States D Bowen
6 6     Italy M Bertolin
United States D Bowen
6 7 6
  Hungary G Köves
Brazil A Sá
4 3     Italy M Bertolin
United States D Bowen
w/o    
  Argentina L Lobo
Chile M Ríos
6 6 6   Argentina L Lobo
Chile M Ríos
     
4 United States B Coupe
South Africa P Rosner
2 7 1   Italy M Bertolin
United States D Bowen
7 6  
  Argentina D del Río
Argentina M Rodríguez
6 7   WC Spain F Mantilla
Chile N Massú
6 3  
Q Argentina Francisco Cabello
Argentina E Medica
3 6     Argentina D del Río
Argentina M Rodríguez
4 6 6
WC Spain F Mantilla
Chile N Massú
6 1 7 WC Spain F Mantilla
Chile N Massú
6 3 7
2 Spain J Alonso
Ecuador N Lapentti
3 6 6

References[edit]