User talk:Feddx

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A talk page[edit]

How droll--Feddx (talk) 19:38, 4 August 2008 (UTC)Feddx[reply]

Photo Change[edit]

If you could revert back to the image David Shanbone preferred, I would appreciate it. I have already reverted twice, and don't want to see to be the only one who feels there was some kind of consensus. Thanks. Atom (talk) 14:35, 8 August 2008 (UTC)[reply]

Photo[edit]

The work you've put in is appreciated, but it does seem you might be overthinking/overcomplicating things for yourself and the page. As it's clear 6 has caused all the problems you've pointed out, but the proponents of 6 have stated they are flexible (Atom and David Shankbone), there doesn't seem to be a conflict. The only thing is to be patient for Shankbone to suggest another photo, as Atom has stated that he is perfectly fine with whichever David chooses. If you could contact David by e-mail and fill him in on the details, that could also speed up the process. A RfC isn't necessary, as it seems everyone's on the same page. Thanks 58.172.32.51 (talk) 05:33, 16 August 2008 (UTC)[reply]

Unless you own the copyright to the lyrics, or have proof that the lyrics are either in the public domain or in a GFDL license, adding lyrics to an article is a copyright violation. Corvus cornixtalk 19:13, 23 September 2008 (UTC)[reply]

I apologize that my edit summary wasn't clear. Corvus cornixtalk 19:28, 23 September 2008 (UTC)[reply]

Addition by subtraction[edit]

In reference to the note on your user page, I thought I'd point out this:

There: addition by subtraction. Cheers. H.G. 20:02, 23 September 2008 (UTC)[reply]

In reference to the formula 1-(-1) = 2 you posted on my talk page as being proof of addition by subtraction. Fine in theory (as I have yet to see -1 of anything), but I can prove that nothing is gained in your equation.

Observe:

A=B.
Multiply both sides by A and you get:
A2=AB.
Add A2 to both sides to get:
A2+A2=A2+AB.
Using addition we get:
2A2=A2+AB.
Subtract 2AB from both sides:
2A2-2AB=A2+AB-2AB.
Thus:
2A2-2AB=A2-AB.
Combining terms on the LHS:
2(A2-AB)= A2-AB.
Divide both sides by (A2-AB):
2(A2-AB)/(A2-AB)= (A2-AB)/(A2-AB).
Cancel out like terms and Viola! We now see:
2 = 1.
So nothing is gained from addition by subtraction.
fin--Feddx (talk) 20:40, 23 September 2008 (UTC)[reply]
Yes, it's a nice example of how pretending one can divide by zero can produce odd results. But it doesn't actually have anything to do with addition by subtraction. H.G. 20:47, 23 September 2008 (UTC)[reply]
So show me (-1) of something to validate your argument. And I mean show me something concrete that I can plainly see is (-1) of some unit. This is the only way your argument is valid. Pretending you can actually have a negative quantity of anything is actually more disturbing.--Feddx (talk) 20:59, 23 September 2008 (UTC)[reply]
I refer you to the article on overdrafts. H.G. 21:09, 23 September 2008 (UTC)[reply]
An overdraft is a concept (as are all credits/bank fees). Not something real. The bank charges you a fee for money you've spent but don't have (if you had the money, you wouldn't get the fee) or you've been extended a credit which you have to pay back. You don't have the money, so a person or an organization takes a financial risk and lends you the money. If it were real you could simply start paying people -10 monetary units and they would be forced to give you 10 monetary units (ah wouldn't that be nice). If you don't pay the fee or penalty or the loan back, and others do the same, the lending organization doesn't just get REAL money back; it becomes insolvent and collapses.
Need proof? Just look at financial state the US is currently in. People think credit is real money. It's not. Sorry. No such thing as negative units of anything in reality. It's only a concept. Fail.--Feddx (talk) 23:39, 23 September 2008 (UTC)[reply]
I'm tempted to argue that reality is conceptual. But instead, I'll say this: you specify a point on the compass, and I'll walk −1 mile in that direction. H.G. 07:22, 24 September 2008 (UTC)[reply]
If reality is conceptual, then why am I talking to you? And no, you'd probably walk 1 mile in the other direction, and tell me it's -1 miles in the desired direction. Not really the same thing (as you'd still be walking 1 mile. Do you know a way to "unwalk" a mile?). It's a matter of "relationships" you'll tell me, to which I'll answer nice try, but still hogwash. There maybe negative quantities in math and conceptual negatives (such as vectors), but there are no concrete negatives in the real "conceptual" world. --Feddx (talk) 11:19, 24 September 2008 (UTC)[reply]

Santo Gold's User page[edit]

I blanked it because it was a redirect out of user-space to article space, and those aren't generally allowed. Ten Pound Hammer and his otters • (Broken clamshellsOtter chirpsHELP) 00:40, 24 September 2008 (UTC)[reply]

File copyright problem with File:Bearly Decent Bill Drea Bear-1980-82.jpg[edit]

Thank you for uploading File:Bearly Decent Bill Drea Bear-1980-82.jpg. However, it currently is missing information on its copyright status. Wikipedia takes copyright very seriously. It may be deleted soon, unless we can determine the license and the source of the file. If you know this information, then you can add a copyright tag to the image description page.

If you have uploaded other files, consider checking that you have specified their license and tagged them, too. You can find a list of files you have created in your upload log.

If you have any questions, please feel free to ask them at the media copyright questions page. Thanks again for your cooperation. Rodhullandemu 23:09, 12 August 2010 (UTC)[reply]

User page[edit]

Hope you don't mind. --88.109.62.31 (talk) 17:14, 22 May 2011 (UTC)[reply]

I do mind. You are NOT supposed to edit people's pages (was reading the header at the top too difficult?). You may talk to me HERE on my TALK PAGE if you're confused about something you read. As for your assertion that sucking out poison from a wound is addition by subtraction, please elaborate. How is this addition? Are you being metaphorical or symbolic?--Feddx (talk) 20:23, 4 April 2012 (UTC)[reply]