2018 Torneo Internacional Challenger León – Doubles

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Doubles
2018 Torneo Internacional Challenger León
Final
ChampionsEcuador Gonzalo Escobar
Mexico Manuel Sánchez
Runners-upAustralia Bradley Mousley
Australia John-Patrick Smith
Score6–4, 6–4
Events
Singles Doubles
← 2017 · Torneo Internacional Challenger León · 2019 →

Leander Paes and Adil Shamasdin were the defending champions but chose not to defend their title.

Gonzalo Escobar and Manuel Sánchez won the title after defeating Bradley Mousley and John-Patrick Smith 6–4, 6–4 in the final.

Seeds[edit]

Draw[edit]

Key[edit]

First round Quarterfinals Semifinals Final
1 El Salvador M Arévalo
Mexico MÁ Reyes-Varela
6 64 [12]
WC Colombia A Gómez
Mexico L Patiño
4 77 [10] 1 El Salvador M Arévalo
Mexico MÁ Reyes-Varela
6 66 [7]
WC Ecuador G Escobar
Mexico M Sánchez
6 6 WC Ecuador G Escobar
Mexico M Sánchez
2 78 [10]
Zimbabwe B Lock
Brazil F Romboli
2 4 WC Ecuador G Escobar
Mexico M Sánchez
6 77
4 Spain A Menéndez Maceiras
Ecuador R Quiroz
6 6 4 Spain A Menéndez Maceiras
Ecuador R Quiroz
1 60
PR Colombia N Barrientos
Serbia D Petrović
4 2 4 Spain A Menéndez Maceiras
Ecuador R Quiroz
6 77
WC Mexico L Gómez
Mexico T Hank
4 5 PR Venezuela LD Martínez
Mexico C Ramírez
4 61
PR Venezuela LD Martínez
Mexico C Ramírez
6 7 WC Ecuador G Escobar
Mexico M Sánchez
6 6
Alt Bolivia B Arias
Canada F Peliwo
2 64 2 Australia B Mousley
Australia J-P Smith
4 4
Argentina F Agamenone
Bolivia F Zeballos
6 77 Argentina F Agamenone
Bolivia F Zeballos
2 65
Venezuela R Maytín
United States D Novikov
6 3 [10] Venezuela R Maytín
United States D Novikov
6 77
3 United Kingdom B Klein
South Africa R Roelofse
3 6 [3] Venezuela R Maytín
United States D Novikov
63 6 [10]
Mexico H Hach Verdugo
Canada B Schnur
6 6 2 Australia B Mousley
Australia J-P Smith
77 4 [12]
Dominican Republic V Estrella Burgos
Peru S Galdós
2 3 Mexico H Hach Verdugo
Canada B Schnur
5 4
Barbados D King
New Zealand R Statham
3 3 2 Australia B Mousley
Australia J-P Smith
7 6
2 Australia B Mousley
Australia J-P Smith
6 6

References[edit]