2016 Samarkand Challenger – Doubles

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Doubles
2016 Samarkand Challenger
Final
ChampionRussia Denis Matsukevich
Belarus Andrei Vasilevski
Runner-upChinese Taipei Hsieh Cheng-peng
Chinese Taipei Yang Tsung-hua
Score6–4, 5–7, [10–5]
Events
Singles Doubles
← 2015 · Samarkand Challenger · 2017 →

Sergey Betov and Mikhail Elgin were the defending champions but lost to Hsieh Cheng-peng and Yang Tsung-hua in the semifinals.

Denis Matsukevich and Andrei Vasilevski won the title after defeating Hsieh Cheng-peng and Yang Tsung-hua 6–4, 5–7, [10–5] in the final.

Seeds[edit]

Draw[edit]

Key[edit]

First round Quarterfinals Semifinals Final
1 Belarus S Betov
Russia M Elgin
w/o
WC Uzbekistan F Dustov
Uzbekistan S Fayziev
1 Belarus S Betov
Russia M Elgin
6 6
Russia A Karatsev
Kazakhstan D Popko
WC Uzbekistan T Ismailov
Georgia (country) A Metreveli
1 0
WC Uzbekistan T Ismailov
Georgia (country) A Metreveli
w/o 1 Belarus S Betov
Russia M Elgin
64 1
4 Chinese Taipei C-p Hsieh
Chinese Taipei T-h Yang
5 7 [12] 4 Chinese Taipei C-p Hsieh
Chinese Taipei T-h Yang
77 6
WC Russia M Kalovelonis
Uzbekistan Shonigmatjon Shofayziyev
7 5 [10] 4 Chinese Taipei C-p Hsieh
Chinese Taipei T-h Yang
6 66 [10]
Uruguay A Behar
Spain E López-Pérez
Moldova R Albot
Belarus I Ivashka
3 78 [6]
Moldova R Albot
Belarus I Ivashka
w/o 4 Chinese Taipei C-p Hsieh
Chinese Taipei T-h Yang
4 7 [5]
Serbia N Milojević
Serbia M Tepavac
w/o PR Russia D Matsukevich
Belarus A Vasilevski
6 5 [10]
Portugal FF Silva
Brazil C Zampieri
Serbia N Milojević
Serbia M Tepavac
Colombia N Barrientos
Canada S Diez
1 4 3 Italy R Ghedin
India J Nedunchezhiyan
w/o
3 Italy R Ghedin
India J Nedunchezhiyan
6 6 3 Italy R Ghedin
India J Nedunchezhiyan
4 0
PR Russia D Matsukevich
Belarus A Vasilevski
64 6 [10] PR Russia D Matsukevich
Belarus A Vasilevski
6 6
Chinese Taipei H-y Peng
Israel A Weintraub
77 4 [8] PR Russia D Matsukevich
Belarus A Vasilevski
6 6
Austria B Trinker
Japan Y Uchiyama
2 South Africa D O'Brien
South Africa R Roelofse
4 4
2 South Africa D O'Brien
South Africa R Roelofse
w/o

References[edit]