1988 Belgian Open – Doubles

From Wikipedia, the free encyclopedia
Doubles
1988 Belgian Open
1987 ChampionsWest Germany Bettina Bunge
Bulgaria Katerina Maleeva
Final
ChampionsArgentina Mercedes Paz
Denmark Tine Scheuer-Larsen
Runners-upBulgaria Katerina Maleeva
Italy Raffaella Reggi
Score7–6, 6–1
Events
Singles Doubles
← 1987 · Belgian Open · 1989 →

Bettina Bunge and Katerina Maleeva were the defending champions but only Maleeva competed that year with Raffaella Reggi.

Maleeva and Reggi lost in the final 7–6, 6–1 against Mercedes Paz and Tine Scheuer-Larsen.

Seeds[edit]

Champion seeds are indicated in bold text while text in italics indicates the round in which those seeds were eliminated.

  1. United States Zina Garrison / United States Kathleen Horvath (quarterfinals)
  2. Argentina Mercedes Paz / Denmark Tine Scheuer-Larsen (champions)
  3. Bulgaria Katerina Maleeva / Italy Raffaella Reggi (final)
  4. Spain Arantxa Sánchez / Belgium Sandra Wasserman (semifinals)

Draw[edit]

Key[edit]

First round Quarterfinals Semifinals Final
1 6 7  
  4 6   1 4 6 6
  6 1     6 1 7
  7 6     3 2  
3 6 5 6 3 6 6  
  4 7 2 3 1 6 6
  6 6     6 4 3
  3 3   3 6 1  
  6 6   2 7 6  
  2 0     0 3  
  4 6   4 6 6  
4 6 7   4 0 6 5
  6 2   2 6 4 7
  4 0 r   1 4  
  1 1   2 6 6  
2 6 6  

References[edit]