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1998 tennis event results
Chanda Rubin was the defending champion, but chose not compete that year.
Jana Novotná won the title, defeating Dominique Van Roost in the final, 6–1, 7–6(7–2) .
A champion seed is indicated in bold text while text in italics indicates the round in which that seed was eliminated. The top four seeds received a bye to the second round.
Section 1 [ edit ]
Section 2 [ edit ]
External links [ edit ]
Grand Slam events Tier I tournaments Tier II tournaments
Sydney (S , D )
Paris (S , D )
Hanover (S , D )
Linz (S , D )
Amelia Island (S , D )
Hamburg (S , D )
Eastbourne (S , D )
Stanford (S , D )
San Diego (S , D )
Los Angeles (S , D )
New Haven (S , D )
Tokyo (S , D )
Filderstadt (S , D )
Leipzig (S , D )
Philadelphia (S , D )
Tier III tournaments
Gold Coast (S , D )
Oklahoma City (S , D )
Tokyo Outdoor (S , D )
Strasbourg (S , D )
Madrid (S , D )
Birmingham (S , D )
Rosmalen (S , D )
Prague (S , D )
Warsaw (S , D )
Boston (S , D )
Quebec City (S , D )
Luxembourg (S , D )
Tier IV tournaments
Auckland (S , D )
Hobart (S , D )
Bogotá (S , D )
Makarska (S , D )
Budapest (S , D )
Bol (S , D )
Maria Lankowitz (S , D )
Palermo (S , D )
Sopot (S , D )
Istanbul (S , D )
Pattaya City (S , D )
Team events