File:Martin Kenzie.jpg

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Non-free media information and use rationale true for Martin Kenzie
Description	Image of deceased British cinematographer - Martin Kenzie (d: 16 July 2012)
Source	http://www.justgiving.com/MartinKenzie
Article	Martin Kenzie
Portion used	Portion of the photograph used.
Low resolution?	Yes
Purpose of use	To identify and illustrate Martin Kenzie
Replaceable?	The subject is dead, so no new photographs can be generated. A free replacement may exist, however, and if this free replacement is located, this image must be deleted.
Fair useFair use of copyrighted material in the context of Martin Kenzie//en.wikipedia.org/wiki/File:Martin_Kenzie.jpgtrue

Licensing[edit]

This work is copyrighted (or assumed to be copyrighted) and unlicensed. It does not fall into one of the blanket acceptable non-free content categories listed at Wikipedia:Non-free content § Images or Wikipedia:Non-free content § Audio clips, and it is not covered by a more specific non-free content license listed at Category:Wikipedia non-free file copyright templates. However, it is believed that the use of this work:

To illustrate the subject in question
Where no free equivalent is available or could be created that would adequately give the same information
On the English-language Wikipedia, hosted on servers in the United States by the non-profit Wikimedia Foundation,

qualifies as fair use under United States copyright law. Any other uses of this image, on Wikipedia or elsewhere, may be copyright infringement. See Wikipedia:Non-free content and Wikipedia:Copyrights.
Fair use

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	Date/Time	Thumbnail	Dimensions	User	Comment
current	00:04, 13 July 2017		267 × 373 (16 KB)	DatBot (talk \| contribs)	Reduce size of non-free image (BOT - disable)
	13:58, 17 April 2013	No thumbnail	400 × 559 (32 KB)	Vivvt (talk \| contribs)	{{Non-free use rationale \|Article = Martin Kenzie \|Description = Image of deceased British cinematographer - Martin Kenzie (d: 16 July 2012) \|Source = http://www.justgiving.com/MartinKenzie \|Portion = Portion of the...

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