File:JulianSandsJorEL.jpg
JulianSandsJorEL.jpg (258 × 387 pixels, file size: 23 KB, MIME type: image/jpeg)
Summary[edit]
| Description |
Screen capture from the Smallville episode "2001-2009" (original air date Dated). featuring Julian Sands as Jor-El in Smallville in episode "Kandor." |
|---|---|
| Source |
Photo: Jack Rowand/The CW ©2009 The CW Network, LLC. All Rights Reserved. TheCW |
| Article | |
| Portion used |
Single frame. |
| Low resolution? |
250px size unsuitable to use for high end reproduction. |
| Purpose of use |
Illustration of a specific point within the article. |
| Replaceable? | |
| Other information |
All DC Comics characters and the distinctive likeness(es) thereof are TM & © DC Comics. © 2001-2009 Warner Bros. Entertainment Inc. ALL RIGHTS RESERVED. Presentation © 2001-2009 Tollin/Robbins Productions and Warner Brothers Television. |
| Fair useFair use of copyrighted material in the context of Jor-El//en.wikipedia.org/wiki/File:JulianSandsJorEL.jpgtrue | |
Licensing[edit]
 | This image is a screenshot of a copyrighted television program. As such, the copyright for it is most likely owned by the company or corporation that produced it. It is believed that the use of a limited number of low-resolution screenshots
qualifies as fair use under the Copyright law of the United States. Any other uses of this image, on Wikipedia or elsewhere, might be copyright infringement. For more information, see Wikipedia:Non-free content. |
File history
Click on a date/time to view the file as it appeared at that time.
| Date/Time | Thumbnail | Dimensions | User | Comment | |
|---|---|---|---|---|---|
| current | 22:41, 14 October 2017 | | 258 × 387 (23 KB) | DatBot (talk | contribs) | Reduce size of non-free image (BOT - disable) |
| 03:27, 10 November 2009 | No thumbnail | 333 × 500 (88 KB) | NeoBatfreak (talk | contribs) | {{Non-free media rationale |Article = Lois Lane | Description = {{Descript-tv-capt|Smallville|2001-2009}} featuring Julian Sands as Jor-El in ''Smallville'' in episode "Kandor." | Source =Pho |
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