File:Areal velocity circle.svg

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English: Image to be used to clarify the concept of areal velocity by the example of uniform circular motion. Here, the area A equals ½ r2 φ = ½ r2 ωt = ½ rvt. Hence, the areal velocity dA/dt equals ½ rv. For uniform circular motion, both r and v are constants of motion; therefore, the areal velocity is also constant.
Date
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Author WillowW
Other versions Linear analogs of this image may be found at Areal_velocity.svg and Areal_velocity2.svg.

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9 August 2010

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9abc2d195fb0507f92aca44c20c421affe02fbf9

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Date/TimeThumbnailDimensionsUserComment
current03:39, 10 August 2010Thumbnail for version as of 03:39, 10 August 2010455 × 450 (7 KB)WillowWAdd φ subscript to ''v'' to clarify that it's the azimuthal velocity. In principle, this change allows this image to be used in general discussions of the specific angular momentum ''h''.
03:20, 10 August 2010Thumbnail for version as of 03:20, 10 August 2010450 × 450 (7 KB)WillowW{{Information |Description={{en|1=Image to be used to clarify the concept of areal velocity by the example of uniform circular motion. Here, the area ''A'' equals ½ ''r''<sup>2</sup> φ = ½ ''r''<sup>2</sup>&nbsp
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