Talk:Atomic nucleus

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20% change from a constant[edit]

article states:

The stable nucleus has approximately a constant density and therefore the nuclear radius R can be approximated by the following formula,

R=r_{0}A^{1/3}\,

where A = Atomic mass number (the number of protons Z, plus the number of neutrons N) and r₀ = 1.25 fm = 1.25 × 10⁻¹⁵ m. In this equation, the constant r₀ varies by 0.2 fm, depending on the nucleus in question, but this is less than 20% change from a constant.

I believe I can explain why the fudge factor varies by 20% (from 1 to 1.35)

https://upload.wikimedia.org/wikipedia/commons/d/d1/Uranium_atom.svg

Just granpa (talk) 02:21, 18 January 2017 (UTC)[reply]

That sounds like WP:original research, is this publiched clearly somehwhere on a reliable source? Graeme Bartlett (talk) 01:56, 20 July 2018 (UTC)[reply]