File:Indianapolis Island Zittel.jpg
Indianapolis_Island_Zittel.jpg (320 × 244 pixels, file size: 43 KB, MIME type: image/jpeg)
| Description |
Indianapolis Island by Andrea Zittell created 2010 photographed 29 Sep 2011. |
|---|---|
| Source | |
| Article | |
| Portion used |
The image shows one side of the copyrighted work of art. |
| Low resolution? |
Yes |
| Purpose of use |
The image serves as the primary means of visual identification of the artwork. |
| Replaceable? |
There is no free equivalent of this artwork's image, so it cannot be replaced by a free image. |
| Other information |
The use of the image will not affect the value of the original work in a negative way or limit the copyright holder's rights or ability to distribute the original. |
| Fair useFair use of copyrighted material in the context of Indianapolis Island//en.wikipedia.org/wiki/File:Indianapolis_Island_Zittel.jpgtrue | |
Licensing[edit]
 | This is a two-dimensional representation of a copyrighted sculpture, statue or any other three-dimensional work of art. As such it is a derivative work of art, and per US Copyright Act of 1976, § 106(2) whoever holds copyright of the original has the exclusive right to authorize derivative works. Per § 107 it is believed that reproduction for criticism, comment, teaching and scholarship constitutes fair use and does not infringe copyright. It is believed that the use of a picture
qualifies as fair use under the Copyright law of the United States. Any other uses of this image, on Wikipedia or elsewhere, might be copyright infringement. |
File history
Click on a date/time to view the file as it appeared at that time.
| Date/Time | Thumbnail | Dimensions | User | Comment | |
|---|---|---|---|---|---|
| current | 22:01, 29 September 2011 | | 320 × 244 (43 KB) | Zambonia (talk | contribs) | {{Non-free use rationale | Description = Indianapolis Island by Andrea Zittell created 2010 photographed 29 Sep 2011. | Source = http://www.facebook.com/photo.php?fbid=549079363616&set=a.546361315606.2042529.22500792&type=1&l=232f6ffcbe& |
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