1999 Open 13 – Doubles

From Wikipedia, the free encyclopedia
Doubles
1999 Open 13
Final
ChampionsBelarus Max Mirnyi
Russia Andrei Olhovskiy
Runners-upSouth Africa David Adams
Czech Republic Pavel Vízner
Score7–5, 7–6
Events
Singles Doubles
← 1998 · Open 13 · 2000 →

Donald Johnson and Francisco Montana were the defending champions, but lost in the semifinals this year.

Max Mirnyi and Andrei Olhovskiy won the title, defeating David Adams and Pavel Vízner 7–5, 7–6 in the final.

Seeds[edit]

Draw[edit]

Key[edit]

Finals[edit]

First round Quarterfinals Semifinals Final
1 Russia Y Kafelnikov
Czech Republic D Vacek
6 1  
  Sweden P Nyborg
Germany D Prinosil
7 6     Sweden P Nyborg
Germany D Prinosil
4 3  
  Italy M Bertolini
Italy C Brandi
6 4   WC France J Golmard
France G Raoux
6 6  
WC France J Golmard
France G Raoux
7 6   WC France J Golmard
France G Raoux
6 1  
3 South Africa P Norval
Zimbabwe K Ullyett
6 7     South Africa D Adams
Czech Republic P Vízner
7 6  
  North Macedonia A Kitinov
United States J Tarango
1 6   3 South Africa P Norval
Zimbabwe K Ullyett
6 2 4
Q Spain J Balcells
Romania A Pavel
3 4     South Africa D Adams
Czech Republic P Vízner
3 6 6
  South Africa D Adams
Czech Republic P Vízner
6 6     South Africa D Adams
Czech Republic P Vízner
5 6  
  United Kingdom N Broad
Netherlands M Oosting
6 3     Belarus M Mirnyi
Russia A Olhovskiy
7 7  
  Belarus M Mirnyi
Russia A Olhovskiy
7 6     Belarus M Mirnyi
Russia A Olhovskiy
7 6  
  United States M Keil
Netherlands T Kempers
7 4 2 4 Spain T Carbonell
United States J Gimelstob
5 4  
4 Spain T Carbonell
United States J Gimelstob
6 6 6   Belarus M Mirnyi
Russia A Olhovskiy
6 6  
WC France A Clément
France N Escudé
6 4 3 2 United States D Johnson
United States F Montana
2 3  
  South Africa L Bale
South Africa M Barnard
1 6 6   South Africa L Bale
South Africa M Barnard
4 2  
WC Spain C Moyá
Russia M Safin
6 7 5 2 United States D Johnson
United States F Montana
6 6  
2 United States D Johnson
United States F Montana
7 5 7

External links[edit]